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Add an @Formula to transpose a list interpreted as a matrix

Lists in formula language are 1-dimensional, but sometimes the data will be interpreted as a matrix (e.g. the elements of a table). An @Formula to transpose the entries of a list by interpreting it as a matrix would be very useful for situations like this, e.g. @Transpose(list, nRows, nCols, [default]) where [default] would fill up holes if @Count(list) != nRows * nCols.

  • Avatar32.5fb70cce7410889e661286fd7f1897de Guest
  • Aug 20 2020
  • Needs review
  • Attach files
  • Avatar40.8f183f721a2c86cd98fddbbe6dc46ec9
    Guest commented
    16 Sep 10:44am

    I'd even more like it if formula language would support lists of lists (of lists ...)

  • Avatar40.8f183f721a2c86cd98fddbbe6dc46ec9
    Guest commented
    4 Sep 10:55am

    In my experience @Transform creates out-of-memory errors if used on larger datasets. There's also no built-in way to get the index of the current entry in @Transform (you can prepend an index if you're transforming strings, but creating an index array is awkward in its own right).

  • Avatar40.8f183f721a2c86cd98fddbbe6dc46ec9
    Guest commented
    21 Aug 03:46pm

    play with @transform. Might do the trick.